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Jojpod Varomc
Registered: Dec 3, 2002
From: O_o
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Posted: Sat Sep 10, 1988 14:38
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I have a problem with my math that calls for immediate solution. The difficulty is with cube root computing formula. I have been looking out for someone who can teach me without delay as my exam is coming near . But it's hard to find someone fast enough besides it being expensive . Can anyone advice ? It will be a huge help.
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espinxh
Registered: Mar 17, 2002
From: Norway
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Posted: Sun Sep 11, 1988 17:32
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Will you please specify what is the nature of problem you are faced with in cube root computing formula? Some more information on this could help to locate ways of solving them. Yes. It can without doubt be hard to find a tutor when time is short and the cost is high. But then you can also decide a program to your taste that is just the right one for you. There are a number of such programs. The solutions are offered on finger tips. It also gives explanation methodically the method in which the answer is reached . This not only gives you the right answers but instructs you to arrive at the correct answer.
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thicxolmed01
Registered: May 16, 2004
From: Welly, NZ
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Posted: Mon Sep 12, 1988 01:43
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I have used various programs to grapple with my difficulties with linear equations, quadratic equations and hyperbolas. Of them, my experience with Algebra Master has been the best . All I had to do was to merely key in the problem. Punch the solve button . The answer appeared almost at once with an easy to understand steps showing how to arrive at the answer. It was simply too easy . Since then I have relied on this Algebra Master for my difficulties with College Algebra, Algebra 1 and Intermediate algebra. I would very much suggest you to try out Algebra Master.
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Techei-Mechial
Registered: Oct 14, 2001
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Posted: Mon Sep 12, 1988 05:46
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I am a regular user of Algebra Master. It not only helps me finish my homework faster, the detailed explanations offered makes understanding the concepts easier. I strongly advise using it to help improve problem solving skills.
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